What is the inverse of y=sqrt(64-(x-2.9)^2)-3 ?

The inverse of y=sqrt(64-(x-2.9)^2)-3 is -(-29+10sqrt(-x^2-6x+55))/(10),(10sqrt(-x^2-6x+55)+29)/(10)

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inverse of y=sqrt(64-(x-2.9)^2)-3

inverse

y = 64 - (x - 2.9)^{2} - 3

- \frac{- 29 + 10 - x ^{2} - 6 x + 55}{10}, \frac{10 - x ^{2} - 6 x + 55 + 29}{10}

Solution steps

y = 64 - (x - 2.9)^{2} - 3

Replace

x

with

y

x = 64 - (y - 2.9)^{2} - 3

Solve for

y, x = 64 - (y - 2.9)^{2} - 3

- \frac{- 29 + 10 - x ^{2} - 6 x + 55}{10}, \frac{10 - x ^{2} - 6 x + 55 + 29}{10}

f (x) = x \frac{1}{3} - 1

\frac{x}{1 + x} + 3

(x + 5)^{2}, x \geq - 5

f (x) = x^{2} \cdot 2

f (x) = 4 - e^{3 x}

What is the inverse of y=sqrt(64-(x-2.9)^2)-3 ?
The inverse of y=sqrt(64-(x-2.9)^2)-3 is -(-29+10sqrt(-x^2-6x+55))/(10),(10sqrt(-x^2-6x+55)+29)/(10)