What is the inverse of f(x)=((4x-9))/(x+2) ?

The inverse of f(x)=((4x-9))/(x+2) is (-9-2x)/(x-4)

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inverse of f(x)=((4x-9))/(x+2)

inverse

f (x) = \frac{( 4 x - 9 )}{x + 2}

\frac{- 9 - 2 x}{x - 4}

Solution steps

y = \frac{4 x - 9}{x + 2}

Replace

x

with

y

x = \frac{4 y - 9}{y + 2}

Solve for

y, x = \frac{4 y - 9}{y + 2}

\frac{- 9 - 2 x}{x - 4}

13 sin (x) + 1

f (x) = \frac{1}{2} (2)^{x}

cos (- \frac{9}{161})

f (x) = 1 0^{(- 1 \cdot \frac{( x + 5 )}{6})}

f (x) = 124.5 + 45 (10) - 0.03 (10)^{2}

What is the inverse of f(x)=((4x-9))/(x+2) ?
The inverse of f(x)=((4x-9))/(x+2) is (-9-2x)/(x-4)