What is the inverse of f(x)=(3x+1)/(4x+7) ?

The inverse of f(x)=(3x+1)/(4x+7) is (1-7x)/(4x-3)

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inverse of f(x)=(3x+1)/(4x+7)

inverse

f (x) = \frac{3 x + 1}{4 x + 7}

\frac{1 - 7 x}{4 x - 3}

Solution steps

y = \frac{3 x + 1}{4 x + 7}

Replace

x

with

y

x = \frac{3 y + 1}{4 y + 7}

Solve for

y, x = \frac{3 y + 1}{4 y + 7}

\frac{1 - 7 x}{4 x - 3}

f (x) = 1 x + 4.1

(x - 1)^{2} - 5

2 x^{2} - 12 x + 3

f (x) = \frac{- 5 x - 7}{2}

e^{x - 3}

What is the inverse of f(x)=(3x+1)/(4x+7) ?
The inverse of f(x)=(3x+1)/(4x+7) is (1-7x)/(4x-3)