What is the inverse of f(x)=21x^2-26x ?

The inverse of f(x)=21x^2-26x is (13+sqrt(21x+169))/(21),(13-sqrt(21x+169))/(21)

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inverse of f(x)=21x^2-26x

inverse

f (x) = 21 x^{2} - 26 x

\frac{13 + 21 x + 169}{21}, \frac{13 - 21 x + 169}{21}

Solution steps

y = 21 x^{2} - 26 x

Replace

x

with

y

x = 21 y^{2} - 26 y

Solve for

y, x = 21 y^{2} - 26 y

\frac{13 + 21 x + 169}{21}, \frac{13 - 21 x + 169}{21}

f (x) = 2 sin (- x + 1)

f (x) = \frac{( x - 2 )}{4}

f (x) = 17 + 2.5 x

f (x) = \frac{( e ^{x} )}{1 + 7 e ^{x}}

\frac{2 x - 1}{x - 1}

What is the inverse of f(x)=21x^2-26x ?
The inverse of f(x)=21x^2-26x is (13+sqrt(21x+169))/(21),(13-sqrt(21x+169))/(21)