What is the inverse of sqrt(3-s)-sqrt(2+s) ?

The inverse of sqrt(3-s)-sqrt(2+s) is (1+ssqrt(-s^2+10))/2 ,(1-ssqrt(-s^2+10))/2

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inverse of sqrt(3-s)-sqrt(2+s)

inverse

3 - s - 2 + s

\frac{1 + s - s ^{2} + 10}{2}, \frac{1 - s - s ^{2} + 10}{2}

Solution steps

y = 3 - s - 2 + s

Replace

s

with

y

s = 3 - y - 2 + y

Solve for

y, s = 3 - y - 2 + y

\frac{1 + s - s ^{2} + 10}{2}, \frac{1 - s - s ^{2} + 10}{2}

y = (x + 4)^{4} + 3, x \geq - 4

\frac{2}{5} x - 4

f (x) = 35 (3)^{x}

\frac{( 2 - j w )}{( - w ^{2} + 4 j w + 3 )}

f (x) = \frac{( x - 2 )}{5}

What is the inverse of sqrt(3-s)-sqrt(2+s) ?
The inverse of sqrt(3-s)-sqrt(2+s) is (1+ssqrt(-s^2+10))/2 ,(1-ssqrt(-s^2+10))/2