What is the inverse of 11s^2+8s+2.5 ?

The inverse of 11s^2+8s+2.5 is (-80+sqrt(4400s-4600))/(220),(-80-sqrt(4400s-4600))/(220)

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inverse of 11s^2+8s+2.5

inverse

11 s^{2} + 8 s + 2.5

\frac{- 80 + 4400 s - 4600}{220}, \frac{- 80 - 4400 s - 4600}{220}

Solution steps

y = 11 s^{2} + 8 s + 2.5

Replace

s

with

y

s = 11 y^{2} + 8 y + 2.5

Solve for

y, s = 11 y^{2} + 8 y + 2.5

\frac{- 80 + 4400 s - 4600}{220}, \frac{- 80 - 4400 s - 4600}{220}

f (x) = ln (\frac{1}{2} x)

f (x) = x + \frac{4.23}{7195 \cdot x}

f (x) = x^{2} - 2 x - 1, 1 \leq x < \infty

49 - x^{2}

f (x) = 2 x^{2} - 2 x - 12

What is the inverse of 11s^2+8s+2.5 ?
The inverse of 11s^2+8s+2.5 is (-80+sqrt(4400s-4600))/(220),(-80-sqrt(4400s-4600))/(220)