What is the inverse of (5z+1)/(4z^2+4z+1) ?

The inverse of (5z+1)/(4z^2+4z+1) is (-4z+5+sqrt(-24z+25))/(8z),(-4z+5-sqrt(-24z+25))/(8z)

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inverse of (5z+1)/(4z^2+4z+1)

inverse

\frac{5 z + 1}{4 z ^{2} + 4 z + 1}

\frac{- 4 z + 5 + - 24 z + 25}{8 z}, \frac{- 4 z + 5 - - 24 z + 25}{8 z}

Solution steps

y = \frac{5 z + 1}{4 z ^{2} + 4 z + 1}

Replace

z

with

y

z = \frac{5 y + 1}{4 y ^{2} + 4 y + 1}

Solve for

y, z = \frac{5 y + 1}{4 y ^{2} + 4 y + 1}

\frac{- 4 z + 5 + - 24 z + 25}{8 z}, \frac{- 4 z + 5 - - 24 z + 25}{8 z}

f (x) = \frac{x ^{2} - 2 x}{x - 2}

40 (x - 1) + 6 + (- 33) (1 - \frac{x}{0.4})^{2}

y = x^{3} - 6

f (x) = 13 - 3 45 - 8

f (x) = 2 x^{2} - x + 3

What is the inverse of (5z+1)/(4z^2+4z+1) ?
The inverse of (5z+1)/(4z^2+4z+1) is (-4z+5+sqrt(-24z+25))/(8z),(-4z+5-sqrt(-24z+25))/(8z)