What is the inverse of Y(x)=x^4+1 ?

The inverse of Y(x)=x^4+1 is \sqrt[4]{x-1},-\sqrt[4]{x-1}

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inverse of Y(x)=x^4+1

inverse

Y (x) = x^{4} + 1

4 x - 1, - 4 x - 1

Solution steps

y = x^{4} + 1

Replace

x

with

y

x = y^{4} + 1

Solve for

y, x = y^{4} + 1

4 x - 1, - 4 x - 1

f (x) = 1 + (\frac{1}{2})^{(x^{2} - 1)}

f (x) = 18 x + 32

\frac{13}{x + 7}

f (x) = - 9 x = 36

(x + 3)^{2} (x - 3)^{2}

What is the inverse of Y(x)=x^4+1 ?
The inverse of Y(x)=x^4+1 is \sqrt[4]{x-1},-\sqrt[4]{x-1}