What is the inverse of f(x)=(x-1)^2,[1,infinity ] ?

The inverse of f(x)=(x-1)^2,[1,infinity ] is sqrt(x)+1,-sqrt(x)+1

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inverse of f(x)=(x-1)^2,[1,infinity ]

inverse

f (x) = (x - 1)^{2}, [1, \infty]

x + 1, - x + 1

Solution steps

y = (x - 1)^{2}

Replace

x

with

y

x = (y - 1)^{2}

Solve for

y, x = (y - 1)^{2}

x + 1, - x + 1

\frac{5 x - 15}{3 x + 7}

5 3 x + 1

\frac{2 x + 3}{5 x - 1}

e^{- \frac{1}{2} x^{2}}

f (x) = 4 - ln (2 - 5 x)

What is the inverse of f(x)=(x-1)^2,[1,infinity ] ?
The inverse of f(x)=(x-1)^2,[1,infinity ] is sqrt(x)+1,-sqrt(x)+1