What is the inverse of f(x)=f(x)= 1/(x+5)-1 ?

The inverse of f(x)=f(x)= 1/(x+5)-1 is (-4-5x)/(x+1)

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inverse of f(x)=f(x)= 1/(x+5)-1

inverse

f (x) = f (x) = \frac{1}{x + 5} - 1

\frac{- 4 - 5 x}{x + 1}

Solution steps

y = \frac{1}{x + 5} - 1

Replace

x

with

y

x = \frac{1}{y + 5} - 1

Solve for

y, x = \frac{1}{y + 5} - 1

\frac{- 4 - 5 x}{x + 1}

y = \frac{1}{x - 2} - 3

f (x) = \frac{( 6 x + 2 )}{x}

sin (0.627)

f (x) = \frac{( - 5 x + 2 )}{6 x + 3}

f (x) = (2 - 3 \cdot arcsec (x))^{3}

What is the inverse of f(x)=f(x)= 1/(x+5)-1 ?
The inverse of f(x)=f(x)= 1/(x+5)-1 is (-4-5x)/(x+1)