What is the inverse of f(x)=e^{x^2-8}=e^{7x} ?

The inverse of f(x)=e^{x^2-8}=e^{7x} is (ln(x))/7

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inverse of f(x)=e^{x^2-8}=e^{7x}

inverse

f (x) = e^{x^{2} - 8} = e^{7 x}

\frac{ln ( x )}{7}

Solution steps

y = e^{7 x}

Replace

x

with

y

x = e^{7 y}

Solve for

y, x = e^{7 y}

\frac{ln ( x )}{7}

11.6 - 4 t

f (x) = \frac{4 - 6 x}{3 - 7 x}

- 0.005 x^{2} + x + 5

y = \frac{4 x - 9}{5}

f (x) = 6 + 3 x + 6

What is the inverse of f(x)=e^{x^2-8}=e^{7x} ?
The inverse of f(x)=e^{x^2-8}=e^{7x} is (ln(x))/7