What is the inverse of f(x)= 1/5 x^3 ?

The inverse of f(x)= 1/5 x^3 is cube root of 5}\sqrt[3]{x

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inverse of f(x)= 1/5 x^3

inverse

f (x) = \frac{1}{5} x^{3}

35 3 x

Solution steps

y = \frac{1}{5} x^{3}

Replace

x

with

y

x = \frac{1}{5} y^{3}

Solve for

y, x = \frac{1}{5} y^{3}

35 3 x

3 x - 11

g (x) = 2 (3)^{x}

f (x) = 8 x^{3} - 3

f (x) = 13 cos (x)

f (x) = 8 x^{2} + 9, x \geq 0

What is the inverse of f(x)= 1/5 x^3 ?
The inverse of f(x)= 1/5 x^3 is cube root of 5}\sqrt[3]{x