What is the inverse of ((-log_{2}(x)+5))/8 ?

The inverse of ((-log_{2}(x)+5))/8 is 2^{-8x+5}

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inverse of ((-log_{2}(x)+5))/8

inverse

\frac{( - lo g _{2} ( x ) + 5 )}{8}

2^{- 8 x + 5}

Solution steps

y = \frac{- lo g _{2} ( x ) + 5}{8}

Replace

x

with

y

x = \frac{- lo g _{2} ( y ) + 5}{8}

Solve for

y, x = \frac{- lo g _{2} ( y ) + 5}{8}

2^{- 8 x + 5}

f (x) = 5 - lo g_{2} (x + 1)

y = - 3 cos (4 x)

f (x) = λ \cdot e^{λ + 3 x}

\frac{d}{d} sec (3 x^{2} + 1)

f (x) = \frac{x + 3}{2 x + 5}

What is the inverse of ((-log_{2}(x)+5))/8 ?
The inverse of ((-log_{2}(x)+5))/8 is 2^{-8x+5}