What is the inverse of 4(x-7)^2+3 ?

The inverse of 4(x-7)^2+3 is (sqrt(x-3))/2+7,-(sqrt(x-3))/2+7

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inverse of 4(x-7)^2+3

inverse

4 (x - 7)^{2} + 3

\frac{x - 3}{2} + 7, - \frac{x - 3}{2} + 7

Solution steps

y = 4 (x - 7)^{2} + 3

Replace

x

with

y

x = 4 (y - 7)^{2} + 3

Solve for

y, x = 4 (y - 7)^{2} + 3

\frac{x - 3}{2} + 7, - \frac{x - 3}{2} + 7

y = - 2 x + 1

f (x) = \frac{6 - x}{3 x}

y = - 2 x + 2

f (x) = \frac{2 x + 6}{9}

\frac{3 s}{s ^{2} - s - 1}

What is the inverse of 4(x-7)^2+3 ?
The inverse of 4(x-7)^2+3 is (sqrt(x-3))/2+7,-(sqrt(x-3))/2+7