What is the inverse of f(x)=x^2-4,x>= 2 ?

The inverse of f(x)=x^2-4,x>= 2 is sqrt(x+4),-sqrt(x+4)

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inverse of f(x)=x^2-4,x>= 2

inverse

f (x) = x^{2} - 4, x \geq 2

x + 4, - x + 4

Solution steps

y = x^{2} - 4

Replace

x

with

y

x = y^{2} - 4

Solve for

y, x = y^{2} - 4

x + 4, - x + 4

f (x) = 7.8019 - 0.7714 x + 0.0149 x^{2}

f (x) = 3 x + 3

5 sin (x) - 4

5 sin (x) - 1

f (x) = \frac{7 - 5 x}{3 x - 1}

What is the inverse of f(x)=x^2-4,x>= 2 ?
The inverse of f(x)=x^2-4,x>= 2 is sqrt(x+4),-sqrt(x+4)