What is the inverse of f(x)=((-4+4x))/(-3-3x) ?

The inverse of f(x)=((-4+4x))/(-3-3x) is -(-4+3x)/(4+3x)

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inverse of f(x)=((-4+4x))/(-3-3x)

inverse

f (x) = \frac{( - 4 + 4 x )}{- 3 - 3 x}

- \frac{- 4 + 3 x}{4 + 3 x}

Solution steps

y = \frac{- 4 + 4 x}{- 3 - 3 x}

Replace

x

with

y

x = \frac{- 4 + 4 y}{- 3 - 3 y}

Solve for

y, x = \frac{- 4 + 4 y}{- 3 - 3 y}

- \frac{- 4 + 3 x}{4 + 3 x}

f (x) = x^{4} - 6

f (x) = x^{4} - 5

f (x) = x^{4} - 8

f (x) = \frac{( 2 x - 3 )}{( 3 x + 1 )}

h (x) = \frac{4 x - 1}{3 x + 7}

What is the inverse of f(x)=((-4+4x))/(-3-3x) ?
The inverse of f(x)=((-4+4x))/(-3-3x) is -(-4+3x)/(4+3x)