What is the inverse of f(x)=\sqrt[3]{2x+9} ?

The inverse of f(x)=\sqrt[3]{2x+9} is (x^3-9)/2

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inverse of f(x)=\sqrt[3]{2x+9}

inverse

f (x) = 3 2 x + 9

\frac{x ^{3} - 9}{2}

Solution steps

y = 3 2 x + 9

Replace

x

with

y

x = 3 2 y + 9

Solve for

y, x = 3 2 y + 9

\frac{x ^{3} - 9}{2}

y = \frac{x}{5} + 9

y = 2 cot (4 x)

- 4 ln (s + 1)

f (x) = 600 - 2 t^{2}

g (x) = - 2 x + 2

What is the inverse of f(x)=\sqrt[3]{2x+9} ?
The inverse of f(x)=\sqrt[3]{2x+9} is (x^3-9)/2