What is the extreme f(x)=x^4e^x-8 ?

The extreme f(x)=x^4e^x-8 is Maximum(-4,(256)/(e^4)-8),Minimum(0,-8)

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extreme f(x)=x^4e^x-8

extreme points

f (x) = x^{4} e^{x} - 8

Maximum (- 4, \frac{256}{e ^{4}} - 8), Minimum (0, - 8)

Solution steps

f^{'} (x) = e^{x} x^{4} + 4 e^{x} x^{3}

Find intervals:

Increasing

: - \infty < x < - 4,

Decreasing

: - 4 < x < 0,

Increasing

: 0 < x < \infty

Plug

x = - 4

into

x^{4} e^{x} - 8 : \frac{256}{e ^{4}} - 8

Maximum (- 4, \frac{256}{e ^{4}} - 8)

Plug

x = 0

into

x^{4} e^{x} - 8 : - 8

Minimum (0, - 8)

Maximum (- 4, \frac{256}{e ^{4}} - 8), Minimum (0, - 8)

f (x) = \frac{8 x - 6}{x - 3}

- x^{3} + 8 x^{2} - 15 x

f (x) = 3^{x} - 2

f (x) = - x^{4} - 7 x^{3} - 12 x^{2}

f (x) = x + 8

What is the extreme f(x)=x^4e^x-8 ?
The extreme f(x)=x^4e^x-8 is Maximum(-4,(256)/(e^4)-8),Minimum(0,-8)