What is the inverse of 1/((s+2)(s+5)) ?

The inverse of 1/((s+2)(s+5)) is (-7s+sqrt(9s^2+4s))/(2s),(-7s-sqrt(9s^2+4s))/(2s)

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inverse of 1/((s+2)(s+5))

inverse

\frac{1}{( s + 2 ) ( s + 5 )}

\frac{- 7 s + 9 s ^{2} + 4 s}{2 s}, \frac{- 7 s - 9 s ^{2} + 4 s}{2 s}

Solution steps

y = \frac{1}{( s + 2 ) ( s + 5 )}

Replace

s

with

y

s = \frac{1}{( y + 2 ) ( y + 5 )}

Solve for

y, s = \frac{1}{( y + 2 ) ( y + 5 )}

\frac{- 7 s + 9 s ^{2} + 4 s}{2 s}, \frac{- 7 s - 9 s ^{2} + 4 s}{2 s}

f (x) = \frac{5 x + 4}{8 x - 7}

ln (11 x^{2} + 3)

\frac{( \frac{8}{5} )}{( \frac{9}{4} )}

f (x) = \frac{1}{8 x} - 3

12000 + 0.25 (x - 40000)

What is the inverse of 1/((s+2)(s+5)) ?
The inverse of 1/((s+2)(s+5)) is (-7s+sqrt(9s^2+4s))/(2s),(-7s-sqrt(9s^2+4s))/(2s)