What is the inverse of f(-2)= 1/2 (x+3)^2 ?

The inverse of f(-2)= 1/2 (x+3)^2 is sqrt(2)sqrt(x)-3,-sqrt(2)sqrt(x)-3

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inverse of f(-2)= 1/2 (x+3)^2

inverse

f (- 2) = \frac{1}{2} (x + 3)^{2}

2 x - 3, - 2 x - 3

Solution steps

y = \frac{1}{2} (x + 3)^{2}

Replace

x

with

y

x = \frac{1}{2} (y + 3)^{2}

Solve for

y, x = \frac{1}{2} (y + 3)^{2}

2 x - 3, - 2 x - 3

f (x) = 4 sin (4 x + 1)

(x - 5)^{3} - 3

x^{2} - 7 x + 10

f (x) = \frac{6}{3 x + 5}

f (x) = cos (2 x + 3)

What is the inverse of f(-2)= 1/2 (x+3)^2 ?
The inverse of f(-2)= 1/2 (x+3)^2 is sqrt(2)sqrt(x)-3,-sqrt(2)sqrt(x)-3