What is the inverse of f(x)=(sqrt(x-1))/(x-4) ?

The inverse of f(x)=(sqrt(x-1))/(x-4) is (8x^2+1+sqrt(12x^2+1))/(2x^2),(8x^2+1-sqrt(12x^2+1))/(2x^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=(sqrt(x-1))/(x-4)

inverse

f (x) = \frac{x - 1}{x - 4}

\frac{8 x ^{2} + 1 + 12 x ^{2} + 1}{2 x ^{2}}, \frac{8 x ^{2} + 1 - 12 x ^{2} + 1}{2 x ^{2}}

Solution steps

y = \frac{x - 1}{x - 4}

Replace

x

with

y

x = \frac{y - 1}{y - 4}

Solve for

y, x = \frac{y - 1}{y - 4}

\frac{8 x ^{2} + 1 + 12 x ^{2} + 1}{2 x ^{2}}, \frac{8 x ^{2} + 1 - 12 x ^{2} + 1}{2 x ^{2}}

\frac{3}{4 + x}

y = \frac{7 x - 9}{9 x + 4}

\frac{( x + 9 )}{x - 3}

f (x) = \frac{3 x - 2}{5 x + 7}

t (x) = - x + 5

What is the inverse of f(x)=(sqrt(x-1))/(x-4) ?
The inverse of f(x)=(sqrt(x-1))/(x-4) is (8x^2+1+sqrt(12x^2+1))/(2x^2),(8x^2+1-sqrt(12x^2+1))/(2x^2)