What is the inverse of \sqrt[5]{(42-10f)/f} ?

The inverse of \sqrt[5]{(42-10f)/f} is (42)/(f^5+10)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of \sqrt[5]{(42-10f)/f}

inverse

5 \frac{42 - 10 f}{f}

\frac{42}{f ^{5} + 10}

Solution steps

y = 5 \frac{42 - 10 f}{f}

Replace

f

with

y

f = 5 \frac{42 - 10 y}{y}

Solve for

y, f = 5 \frac{42 - 10 y}{y}

\frac{42}{f ^{5} + 10}

f (x) = 2 y^{2} + 15

f (x) = - x^{- 2} + 1

f (x) = 5 ln (x^{2} + 1) - 2

f (x) = y^{3} + 6

\frac{1}{2 x - 2}

What is the inverse of \sqrt[5]{(42-10f)/f} ?
The inverse of \sqrt[5]{(42-10f)/f} is (42)/(f^5+10)