What is the inverse of f(x)=-x^2+25,x>= 25 ?

The inverse of f(x)=-x^2+25,x>= 25 is sqrt(-x+25),-sqrt(-x+25)

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inverse of f(x)=-x^2+25,x>= 25

inverse

f (x) = - x^{2} + 25, x \geq 25

- x + 25, - - x + 25

Solution steps

y = - x^{2} + 25

Replace

x

with

y

x = - y^{2} + 25

Solve for

y, x = - y^{2} + 25

- x + 25, - - x + 25

f (x) = 4 - 5 x + 2

f (x) = 7^{(x)} - 5

cot (6 x)

f (x) = \frac{2}{5} x + 15

f (x) = \frac{( sin ( x + 1 ) )}{3}

What is the inverse of f(x)=-x^2+25,x>= 25 ?
The inverse of f(x)=-x^2+25,x>= 25 is sqrt(-x+25),-sqrt(-x+25)