What is the inverse of f(x)=f(a)=-4a^2-3 ?

The inverse of f(x)=f(a)=-4a^2-3 is sqrt(-(a+3)/4),-sqrt(-(a+3)/4)

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inverse of f(x)=f(a)=-4a^2-3

inverse

f (x) = f (a) = - 4 a^{2} - 3

- \frac{a + 3}{4}, - - \frac{a + 3}{4}

Solution steps

y = - 4 a^{2} - 3

Replace

a

with

y

a = - 4 y^{2} - 3

Solve for

y, a = - 4 y^{2} - 3

- \frac{a + 3}{4}, - - \frac{a + 3}{4}

f (x) = \frac{7 x - 1}{2 x + 5}

f (x) = 3 - ln (x + 2)

f (x) = \frac{100}{x - 12} + 8

y = e^{x} + 2

(y + 5)^{2} + 8 x = 16

What is the inverse of f(x)=f(a)=-4a^2-3 ?
The inverse of f(x)=f(a)=-4a^2-3 is sqrt(-(a+3)/4),-sqrt(-(a+3)/4)