What is the inverse of f(x)=\sqrt[3]{2x+1} ?

The inverse of f(x)=\sqrt[3]{2x+1} is (x^3-1)/2

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inverse of f(x)=\sqrt[3]{2x+1}

inverse

f (x) = 3 2 x + 1

\frac{x ^{3} - 1}{2}

Solution steps

y = 3 2 x + 1

Replace

x

with

y

x = 3 2 y + 1

Solve for

y, x = 3 2 y + 1

\frac{x ^{3} - 1}{2}

f (x) = \frac{9}{4 - x}

f (x) = 3 x - Y (x) = 8

y = e^{6} - x

f (x) = 17 3 x

- \frac{1}{2 x ^{2}}

What is the inverse of f(x)=\sqrt[3]{2x+1} ?
The inverse of f(x)=\sqrt[3]{2x+1} is (x^3-1)/2