What is the inverse of f(x)=((x+2))/(3x+1) ?

The inverse of f(x)=((x+2))/(3x+1) is (2-x)/(3x-1)

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inverse of f(x)=((x+2))/(3x+1)

inverse

f (x) = \frac{( x + 2 )}{3 x + 1}

\frac{2 - x}{3 x - 1}

Solution steps

y = \frac{x + 2}{3 x + 1}

Replace

x

with

y

x = \frac{y + 2}{3 y + 1}

Solve for

y, x = \frac{y + 2}{3 y + 1}

\frac{2 - x}{3 x - 1}

\frac{2 s + 3}{s ^{2} + 9}

h (t) = - 16 t^{2} + 30 t + 5

f (x) = 1.25 (38 - x)

y = 9 x

arccos (- 4)

What is the inverse of f(x)=((x+2))/(3x+1) ?
The inverse of f(x)=((x+2))/(3x+1) is (2-x)/(3x-1)