What is the inverse of f(x)=4^{0.02x} ?

The inverse of f(x)=4^{0.02x} is (ln(x))/(0.04ln(2))

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inverse of f(x)=4^{0.02x}

inverse

f (x) = 4^{0.02 x}

\frac{ln ( x )}{0.04 ln ( 2 )}

Solution steps

y = 4^{0.02 x}

Replace

x

with

y

x = 4^{0.02 y}

Solve for

y, x = 4^{0.02 y}

\frac{ln ( x )}{0.04 ln ( 2 )}

y = \frac{5}{5 x}

x^{2} + 8 x - 9

f (x) = \frac{10 x + 5}{- 9 x - 3}

f (x) = \frac{- 5}{3 x + 2}

arctan (y)

What is the inverse of f(x)=4^{0.02x} ?
The inverse of f(x)=4^{0.02x} is (ln(x))/(0.04ln(2))