What is the inverse of f(x)=3*2^{x-1}+1 ?

The inverse of f(x)=3*2^{x-1}+1 is (ln((x-1)/3))/(ln(2))+1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=3*2^{x-1}+1

inverse

f (x) = 3 \cdot 2^{x - 1} + 1

\frac{ln ( \frac{x - 1}{3} )}{ln ( 2 )} + 1

Solution steps

y = 3 \cdot 2^{x - 1} + 1

Replace

x

with

y

x = 3 \cdot 2^{y - 1} + 1

Solve for

y, x = 3 \cdot 2^{y - 1} + 1

\frac{ln ( \frac{x - 1}{3} )}{ln ( 2 )} + 1

f (x) = lo g_{10} (x + 1) - 4

y = - 2^{x}

2 \frac{3 x ^{2}}{x}

\frac{20}{1 + e ^{- 0.3 \cdot (t - 15)}}

f (x) = 2 (\frac{x - 5}{2}) + 5

What is the inverse of f(x)=3*2^{x-1}+1 ?
The inverse of f(x)=3*2^{x-1}+1 is (ln((x-1)/3))/(ln(2))+1