What is the inverse of f(x)=-(x+1)2-1,x<-pi/2 ?

The inverse of f(x)=-(x+1)2-1,x<-pi/2 is -(x+1)/2-1

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inverse of f(x)=-(x+1)2-1,x<-pi/2

inverse

f (x) = - (x + 1) 2 - 1, x < - \frac{π}{2}

- \frac{x + 1}{2} - 1

Solution steps

y = - (x + 1) \cdot 2 - 1

Replace

x

with

y

x = - (y + 1) \cdot 2 - 1

Solve for

y, x = - (y + 1) 2 - 1

- \frac{x + 1}{2} - 1

\frac{6 x}{x - 4}

f (x) = \frac{( 2 x + 5 )}{( x - 11 )}

\frac{( x - 1 ) ^{7} + 5}{3}

f (x) = \frac{( x ^{2} - 1 )}{( x ^{2} - 4 )}

6 - lo g_{5} (2 x - 7)

What is the inverse of f(x)=-(x+1)2-1,x<-pi/2 ?
The inverse of f(x)=-(x+1)2-1,x<-pi/2 is -(x+1)/2-1