What is the inverse of (x-3)^2+7sqrt(4-7)+3 ?

The inverse of (x-3)^2+7sqrt(4-7)+3 is None

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inverse of (x-3)^2+7sqrt(4-7)+3

inverse

(x - 3)^{2} + 7 4 - 7 + 3

None

Solution steps

y = (x - 3)^{2} + 7 4 - 7 + 3

Replace

x

with

y

x = (y - 3)^{2} + 7 4 - 7 + 3

Solve for

y, x = (y - 3)^{2} + 7 4 - 7 + 3

Therefore, there are no inverse functions for

(x - 3)^{2} + 7 4 - 7 + 3

None

\frac{2 x + 3}{3 x ^{2}}

\frac{( x + 3 )}{( x + 8 )}

f (x) = \frac{( - 2 x + 9 )}{x - 3}

(x + 7) 2

f (x) = 1 6^{x}

What is the inverse of (x-3)^2+7sqrt(4-7)+3 ?
The inverse of (x-3)^2+7sqrt(4-7)+3 is None