What is the inverse of log_{10}(X-1)-log_{10}(X) ?

The inverse of log_{10}(X-1)-log_{10}(X) is -1/(10^X-1)

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inverse of log_{10}(X-1)-log_{10}(X)

inverse

lo g_{10} (X - 1) - lo g_{10} (X)

- \frac{1}{1 0 ^{X} - 1}

Solution steps

y = lo g_{10} (X - 1) - lo g_{10} (X)

Replace

X

with

y

X = lo g_{10} (y - 1) - lo g_{10} (y)

Solve for

y, X = lo g_{10} (y - 1) - lo g_{10} (y)

- \frac{1}{1 0 ^{X} - 1}

f (x) = 5 8 (x + 9) - 7

f (x) = \frac{9 x}{6 - x}

f (x) = 19.94

f (x) = 7 + 4 x - 5

f (x) = 1 - e^{- λ x}

What is the inverse of log_{10}(X-1)-log_{10}(X) ?
The inverse of log_{10}(X-1)-log_{10}(X) is -1/(10^X-1)