What is the inverse of 1/(s(s+1/10)) ?

The inverse of 1/(s(s+1/10)) is (-s+sqrt(s^2+400s))/(20s),(-s-sqrt(s^2+400s))/(20s)

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inverse of 1/(s(s+1/10))

inverse

\frac{1}{s ( s + \frac{1}{10} )}

\frac{- s + s ^{2} + 400 s}{20 s}, \frac{- s - s ^{2} + 400 s}{20 s}

Solution steps

y = \frac{1}{s ( s + \frac{1}{10} )}

Replace

s

with

y

s = \frac{1}{y ( y + \frac{1}{10} )}

Solve for

y, s = \frac{1}{y ( y + \frac{1}{10} )}

\frac{- s + s ^{2} + 400 s}{20 s}, \frac{- s - s ^{2} + 400 s}{20 s}

x - 3 + 8

2 x^{2} + 3 x + 4

f (x) = \frac{( x - 3 )}{2} + 4

\frac{1}{s ^{2} + 4 s + 5}

f (x) = \frac{x - 4}{2} + 2

What is the inverse of 1/(s(s+1/10)) ?
The inverse of 1/(s(s+1/10)) is (-s+sqrt(s^2+400s))/(20s),(-s-sqrt(s^2+400s))/(20s)