What is the inverse of f(x)=3y^2+(-6)/4 ?

The inverse of f(x)=3y^2+(-6)/4 is sqrt((2y+3)/6),-sqrt((2y+3)/6)

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inverse of f(x)=3y^2+(-6)/4

inverse

f (x) = 3 y^{2} + \frac{- 6}{4}

\frac{2 y + 3}{6}, - \frac{2 y + 3}{6}

Solution steps

x = 3 y^{2} + \frac{- 6}{4}

Replace

y

with

x

y = 3 x^{2} + \frac{- 6}{4}

Solve for

x, y = 3 x^{2} + \frac{- 6}{4}

\frac{2 y + 3}{6}, - \frac{2 y + 3}{6}

+ x + 3 x - 5

y = 1 + tan (π x)

f (x) = 6 x^{4} + 9 x^{2}

f (x) = 5 3 x

f (x) = - 2 x^{2} + 13

What is the inverse of f(x)=3y^2+(-6)/4 ?
The inverse of f(x)=3y^2+(-6)/4 is sqrt((2y+3)/6),-sqrt((2y+3)/6)