What is the inverse of f(x)=x^2-4x+4,x<= 0 ?

The inverse of f(x)=x^2-4x+4,x<= 0 is 2+sqrt(x),2-sqrt(x)

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inverse of f(x)=x^2-4x+4,x<= 0

inverse

f (x) = x^{2} - 4 x + 4, x \leq 0

2 + x, 2 - x

Solution steps

y = x^{2} - 4 x + 4

Replace

x

with

y

x = y^{2} - 4 y + 4

Solve for

y, x = y^{2} - 4 y + 4

2 + x, 2 - x

6 x + 12

3 3 2 a - 6 3 2 a

f (x) = \frac{2 x + 1}{x - 9}

f (x) = \frac{x - 2}{x + 2}

- \frac{14}{z - 2}

What is the inverse of f(x)=x^2-4x+4,x<= 0 ?
The inverse of f(x)=x^2-4x+4,x<= 0 is 2+sqrt(x),2-sqrt(x)