What is the inverse of 2^{-1+x^2} ?

The inverse of 2^{-1+x^2} is sqrt((ln(2x))/(ln(2))),-sqrt((ln(2x))/(ln(2)))

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inverse of 2^{-1+x^2}

inverse

2^{- 1 + x^{2}}

\frac{ln ( 2 x )}{ln ( 2 )}, - \frac{ln ( 2 x )}{ln ( 2 )}

Solution steps

y = 2^{- 1 + x^{2}}

Replace

x

with

y

x = 2^{- 1 + y^{2}}

Solve for

y, x = 2^{- 1 + y^{2}}

\frac{ln ( 2 x )}{ln ( 2 )}, - \frac{ln ( 2 x )}{ln ( 2 )}

y = x^{\frac{1}{3}} + 5

\frac{4}{3}

f (x) = x - 3 - 2

f (x) = \frac{2 x ^{2} - 1}{3 x}

\frac{8 x - 6}{9 x - 5}

What is the inverse of 2^{-1+x^2} ?
The inverse of 2^{-1+x^2} is sqrt((ln(2x))/(ln(2))),-sqrt((ln(2x))/(ln(2)))