What is the inverse of y=(-8x+x^2+12)/(12) ?

The inverse of y=(-8x+x^2+12)/(12) is 2(sqrt(3x+1)+2),2(-sqrt(3x+1)+2)

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inverse of y=(-8x+x^2+12)/(12)

inverse

y = \frac{- 8 x + x ^{2} + 12}{12}

2 (3 x + 1 + 2), 2 (- 3 x + 1 + 2)

Solution steps

y = \frac{- 8 x + x ^{2} + 12}{12}

Replace

x

with

y

x = \frac{- 8 y + y ^{2} + 12}{12}

Solve for

y, x = \frac{- 8 y + y ^{2} + 12}{12}

2 (3 x + 1 + 2), 2 (- 3 x + 1 + 2)

y = - 5 x - 5 + 5

y = - \frac{1}{2} x + 3

f (x) = 1 - 2 \cdot x^{2}

\frac{z}{( 2 z - 1 )}

f (x) = f (x) = 78 - 10 x + 5

What is the inverse of y=(-8x+x^2+12)/(12) ?
The inverse of y=(-8x+x^2+12)/(12) is 2(sqrt(3x+1)+2),2(-sqrt(3x+1)+2)