What is the inverse of f(x)=7-4/(x^2) ?

The inverse of f(x)=7-4/(x^2) is sqrt(-4/(x-7)),-sqrt(-4/(x-7))

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inverse of f(x)=7-4/(x^2)

inverse

f (x) = 7 - \frac{4}{x ^{2}}

- \frac{4}{x - 7}, - - \frac{4}{x - 7}

Solution steps

y = 7 - \frac{4}{x ^{2}}

Replace

x

with

y

x = 7 - \frac{4}{y ^{2}}

Solve for

y, x = 7 - \frac{4}{y ^{2}}

- \frac{4}{x - 7}, - - \frac{4}{x - 7}

f (x) = \frac{3}{8} x^{7}

f (3) = 5 x + 1

f (x) = \frac{14000}{0.3}

f - 1

lo g_{5} (8)

What is the inverse of f(x)=7-4/(x^2) ?
The inverse of f(x)=7-4/(x^2) is sqrt(-4/(x-7)),-sqrt(-4/(x-7))