What is the inverse of f(x)=4*log_{1/2}(-x+10) ?

The inverse of f(x)=4*log_{1/2}(-x+10) is -(1/2)^{x/4}+10

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inverse of f(x)=4*log_{1/2}(-x+10)

inverse

f (x) = 4 \cdot lo g_{\frac{1}{2}} (- x + 10)

- (\frac{1}{2})^{\frac{x}{4}} + 10

Solution steps

y = 4 lo g_{\frac{1}{2}} (- x + 10)

Replace

x

with

y

x = 4 lo g_{\frac{1}{2}} (- y + 10)

Solve for

y, x = 4 \cdot lo g_{\frac{1}{2}} (- y + 10)

- (\frac{1}{2})^{\frac{x}{4}} + 10

f (x) = \frac{x ^{2} - 1}{x ^{2} - 9}

f (x) = Y (x) (x)^{1} = \frac{x - 4}{2} + 3

(x - 7)^{3} + 8

\frac{1}{85 - 3}

f (x) = (\frac{8}{x})^{3}

What is the inverse of f(x)=4*log_{1/2}(-x+10) ?
The inverse of f(x)=4*log_{1/2}(-x+10) is -(1/2)^{x/4}+10