What is the inverse of f(x)= 1/4 sqrt(x-1)-2 ?

The inverse of f(x)= 1/4 sqrt(x-1)-2 is 16x^2+64x+65

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inverse of f(x)= 1/4 sqrt(x-1)-2

inverse

f (x) = \frac{1}{4} x - 1 - 2

16 x^{2} + 64 x + 65

Solution steps

y = \frac{1}{4} x - 1 - 2

Replace

x

with

y

x = \frac{1}{4} y - 1 - 2

Solve for

y, x = \frac{1}{4} y - 1 - 2

16 x^{2} + 64 x + 65

f (x) = 2 (x - 4) 2 - 8

\frac{- 1 - 7 x}{5 x - 3}

f (x) = \frac{( 2 x - 3 )}{x - 2}

f (x) = (0, - 2)

\frac{3 x}{4 x - 5}

What is the inverse of f(x)= 1/4 sqrt(x-1)-2 ?
The inverse of f(x)= 1/4 sqrt(x-1)-2 is 16x^2+64x+65