What is the inverse of (-2s-8)/(s^2+4s+4) ?

The inverse of (-2s-8)/(s^2+4s+4) is (-2s-1+sqrt(-4s+1))/s ,-(2s+sqrt(-4s+1)+1)/s

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inverse of (-2s-8)/(s^2+4s+4)

inverse

\frac{- 2 s - 8}{s ^{2} + 4 s + 4}

\frac{- 2 s - 1 + - 4 s + 1}{s}, - \frac{2 s + - 4 s + 1 + 1}{s}

Solution steps

y = \frac{- 2 s - 8}{s ^{2} + 4 s + 4}

Replace

s

with

y

s = \frac{- 2 y - 8}{y ^{2} + 4 y + 4}

Solve for

y, s = \frac{- 2 y - 8}{y ^{2} + 4 y + 4}

\frac{- 2 s - 1 + - 4 s + 1}{s}, - \frac{2 s + - 4 s + 1 + 1}{s}

g (x) = \frac{( 7 x + 18 )}{2}

cos (\frac{5}{12})

\frac{2}{s + 3}

f (- 4) = \frac{x + 4}{x + 7}

\frac{s + 4}{s + 8}

What is the inverse of (-2s-8)/(s^2+4s+4) ?
The inverse of (-2s-8)/(s^2+4s+4) is (-2s-1+sqrt(-4s+1))/s ,-(2s+sqrt(-4s+1)+1)/s