What is the inverse of y=((2x+1))/(3-2x) ?

The inverse of y=((2x+1))/(3-2x) is -(1-3x)/(2(1+x))

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inverse of y=((2x+1))/(3-2x)

inverse

y = \frac{( 2 x + 1 )}{3 - 2 x}

- \frac{1 - 3 x}{2 ( 1 + x )}

Solution steps

y = \frac{2 x + 1}{3 - 2 x}

Replace

x

with

y

x = \frac{2 y + 1}{3 - 2 y}

Solve for

y, x = \frac{2 y + 1}{3 - 2 y}

- \frac{1 - 3 x}{2 ( 1 + x )}

f (x) = lo g_{e} (3 x)

123056709

f (x) = \frac{( x - 4 )}{( x + 2 )}

y = \frac{x + \frac{65}{21}}{\frac{5}{21}}

x = 15

What is the inverse of y=((2x+1))/(3-2x) ?
The inverse of y=((2x+1))/(3-2x) is -(1-3x)/(2(1+x))