What is the domain of f(x)=sqrt(5-x)+sqrt(6+x) ?

The domain of f(x)=sqrt(5-x)+sqrt(6+x) is -6<= x<= 5

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domain of f(x)=sqrt(5-x)+sqrt(6+x)

domain

f (x) = 5 - x + 6 + x

- 6 \leq x \leq 5

Interval Notation

[- 6, 5]

Solution steps

Find non-negative values for radicals:

- 6 \leq x \leq 5

The function domain

- 6 \leq x \leq 5

f (x) = 4 sin (2 x - \frac{π}{3}) + 1

\frac{3 x}{x + 2}

f (x) = x^{2} - 11, x \geq 0

f (x) = \frac{10}{x ^{2} - 1}

f (x) = \frac{- 2 x + 1}{x ^{2} + x - 6}

What is the domain of f(x)=sqrt(5-x)+sqrt(6+x) ?
The domain of f(x)=sqrt(5-x)+sqrt(6+x) is -6<= x<= 5