What is the inverse of 1/(s+1)-1/(s+2) ?

The inverse of 1/(s+1)-1/(s+2) is (-3s+sqrt(s^2+4s))/(2s),(-3s-sqrt(s^2+4s))/(2s)

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inverse of 1/(s+1)-1/(s+2)

inverse

\frac{1}{s + 1} - \frac{1}{s + 2}

\frac{- 3 s + s ^{2} + 4 s}{2 s}, \frac{- 3 s - s ^{2} + 4 s}{2 s}

Solution steps

y = \frac{1}{s + 1} - \frac{1}{s + 2}

Replace

s

with

y

s = \frac{1}{y + 1} - \frac{1}{y + 2}

Solve for

y, s = \frac{1}{y + 1} - \frac{1}{y + 2}

\frac{- 3 s + s ^{2} + 4 s}{2 s}, \frac{- 3 s - s ^{2} + 4 s}{2 s}

f (x) = \frac{3 ( x + 3 )}{2} + 4

y = \frac{4 x}{x + 1}

m + \frac{1}{x}

\frac{1}{x} - 4

\frac{2 x + 8}{x + 3}

What is the inverse of 1/(s+1)-1/(s+2) ?
The inverse of 1/(s+1)-1/(s+2) is (-3s+sqrt(s^2+4s))/(2s),(-3s-sqrt(s^2+4s))/(2s)