What is the inverse of f(x)=x^2-4x+17 ?

The inverse of f(x)=x^2-4x+17 is 2+sqrt(x-13),2-sqrt(x-13)

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inverse of f(x)=x^2-4x+17

inverse

f (x) = x^{2} - 4 x + 17

2 + x - 13, 2 - x - 13

Solution steps

y = x^{2} - 4 x + 17

Replace

x

with

y

x = y^{2} - 4 y + 17

Solve for

y, x = y^{2} - 4 y + 17

2 + x - 13, 2 - x - 13

f (x) = 0.25 x

f (x) = \frac{2 x - 3}{x + 3}

9 y - 8

f (x) = 18 ln (tan (x))

f (x) = \frac{x + 1}{3 x + 4}

What is the inverse of f(x)=x^2-4x+17 ?
The inverse of f(x)=x^2-4x+17 is 2+sqrt(x-13),2-sqrt(x-13)