What is the inverse of f(x)=\sqrt[3]{x-10}+8 ?

The inverse of f(x)=\sqrt[3]{x-10}+8 is x^3-24x^2+192x-502

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inverse of f(x)=\sqrt[3]{x-10}+8

inverse

f (x) = 3 x - 10 + 8

x^{3} - 24 x^{2} + 192 x - 502

Solution steps

y = 3 x - 10 + 8

Replace

x

with

y

x = 3 y - 10 + 8

Solve for

y, x = 3 y - 10 + 8

x^{3} - 24 x^{2} + 192 x - 502

f (x) = 3 x - 10 + 4

ln (x) 4.77

\frac{4 x}{3 x - 5}

\frac{8}{x + 5}

f (x) = \frac{2 x + 3}{4 x - 1}

What is the inverse of f(x)=\sqrt[3]{x-10}+8 ?
The inverse of f(x)=\sqrt[3]{x-10}+8 is x^3-24x^2+192x-502