What is the inverse of f(x)=x^2-18x+81 ?

The inverse of f(x)=x^2-18x+81 is 9+sqrt(x),9-sqrt(x)

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inverse of f(x)=x^2-18x+81

inverse

f (x) = x^{2} - 18 x + 81

9 + x, 9 - x

Solution steps

y = x^{2} - 18 x + 81

Replace

x

with

y

x = y^{2} - 18 y + 81

Solve for

y, x = y^{2} - 18 y + 81

9 + x, 9 - x

f (x) = 9 \cdot 2^{2 x - 1} - 1

f (x) = 5 - \frac{1}{2} x

y = \frac{5 x - 3}{x}

f (x) = x^{2} + 4 x + 5, x \leq - 2

- 5 x - 6

What is the inverse of f(x)=x^2-18x+81 ?
The inverse of f(x)=x^2-18x+81 is 9+sqrt(x),9-sqrt(x)