What is the inverse of f(x)= 1/2 x^2-8 ?

The inverse of f(x)= 1/2 x^2-8 is sqrt(2x+16),-sqrt(2x+16)

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inverse of f(x)= 1/2 x^2-8

inverse

f (x) = \frac{1}{2} x^{2} - 8

2 x + 16, - 2 x + 16

Solution steps

y = \frac{1}{2} x^{2} - 8

Replace

x

with

y

x = \frac{1}{2} y^{2} - 8

Solve for

y, x = \frac{1}{2} y^{2} - 8

2 x + 16, - 2 x + 16

f (x) = - x^{2} + 1, x \geq 0

f (x) = - 2 (x + 1)^{3}

\frac{x ^{2} - 4}{x - 2}

y = 2^{x - 1} + 5

f (x) = \frac{5 x + 4 - 4}{5}

What is the inverse of f(x)= 1/2 x^2-8 ?
The inverse of f(x)= 1/2 x^2-8 is sqrt(2x+16),-sqrt(2x+16)