What is the inverse of f(x)=1-e^{(-0.03*x^{1.2})} ?

The inverse of f(x)=1-e^{(-0.03*x^{1.2})} is 18.58085…(-ln(1-x))^{5/6}

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inverse of f(x)=1-e^{(-0.03*x^{1.2})}

inverse

f (x) = 1 - e^{(- 0.03 \cdot x^{1.2})}

18.58085 \dots (- ln (1 - x))^{\frac{5}{6}}

Solution steps

y = 1 - e^{- 0.03 x^{1.2}}

Replace

x

with

y

x = 1 - e^{- 0.03 y^{1.2}}

Solve for

y, x = 1 - e^{- 0.03 \cdot y^{1.2}}

18.58085 \dots (- ln (1 - x))^{\frac{5}{6}}

ln (5 x + 7)

f (x) = 3 ln (3^{x}) + 1

\frac{3}{y - 2} + 2

f (x) = 10 x - 8

\frac{x ^{2} + 1}{x ^{2}}

What is the inverse of f(x)=1-e^{(-0.03*x^{1.2})} ?
The inverse of f(x)=1-e^{(-0.03*x^{1.2})} is 18.58085…(-ln(1-x))^{5/6}