What is the inverse of f(x)=x^{(-3/2)} ?

The inverse of f(x)=x^{(-3/2)} is cube root of 1/(x^2)

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inverse of f(x)=x^{(-3/2)}

inverse

f (x) = x^{(- \frac{3}{2})}

3 \frac{1}{x ^{2}}

Solution steps

y = x^{- \frac{3}{2}}

Replace

x

with

y

x = y^{- \frac{3}{2}}

Solve for

y, x = y^{- \frac{3}{2}}

3 \frac{1}{x ^{2}}

\frac{25}{10} \frac{15}{x}

f (x) = 3 x + 11 + 12

x = 0.4 t + 6.6

y = 2 x + 10

y = (x - 4)^{3}

What is the inverse of f(x)=x^{(-3/2)} ?
The inverse of f(x)=x^{(-3/2)} is cube root of 1/(x^2)