What is the inverse of ((x-5)(x-3))/(x+5) ?

The inverse of ((x-5)(x-3))/(x+5) is (8+x+sqrt(x^2+36x+4))/2 ,(8+x-sqrt(x^2+36x+4))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of ((x-5)(x-3))/(x+5)

inverse

\frac{( x - 5 ) ( x - 3 )}{x + 5}

\frac{8 + x + x ^{2} + 36 x + 4}{2}, \frac{8 + x - x ^{2} + 36 x + 4}{2}

Solution steps

y = \frac{( x - 5 ) ( x - 3 )}{x + 5}

Replace

x

with

y

x = \frac{( y - 5 ) ( y - 3 )}{y + 5}

Solve for

y, x = \frac{( y - 5 ) ( y - 3 )}{y + 5}

\frac{8 + x + x ^{2} + 36 x + 4}{2}, \frac{8 + x - x ^{2} + 36 x + 4}{2}

2 - x + 5

9 - x^{2}, 0 \leq x \leq 3, x = 2

f (x) = x + 4 = x^{2}

f (x) = 5 x - 50

k (x) = \frac{x - 1}{x + 7}

What is the inverse of ((x-5)(x-3))/(x+5) ?
The inverse of ((x-5)(x-3))/(x+5) is (8+x+sqrt(x^2+36x+4))/2 ,(8+x-sqrt(x^2+36x+4))/2